5x^2+14x-168=0

Solution for 5x^2+14x-168=0 equation:

5x^2+14x-168=0

a = 5; b = 14; c = -168;
Δ = b2-4ac
Δ = 142-4·5·(-168)
Δ = 3556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3556}=\sqrt{4*889}=\sqrt{4}*\sqrt{889}=2\sqrt{889}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{889}}{2*5}=\frac{-14-2\sqrt{889}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{889}}{2*5}=\frac{-14+2\sqrt{889}}{10}
$